Q:
Strictly hypothetically question: If I wanted to construct a six hundred and forty acre bass pond with an average depth of eleven feet and I had an artesian well that produces 30,043.44 pounds of water per hour. How long would it take to fill it up, not counting rain or eveperation, just water from the well?
Question by santa. Uploaded on January 28, 2012
Answers (9)
Assuming that this is not a trick question, my best guess would be about 70 years, but I am no great mathematician.
One acre = 43,560 square feet so we're talking 306,662,400 cubic feet for 160 acres 11 feet deep.
One US gallon is 0.133681 cubic feet so we're looking at 2,293,986,430 gallons for full pool. (at roughly room temp and sea level)
One US gallon weighes 8.345404 pounds (at roughly room temp and sea level). So, we're talking about 3600 gallons per hour.
Therefore, it will take 637,218 hours or about 72 years, 8 months, 9 days.
Of course my calculations and assumptions could be wrong...
I think pig hunter got it. My quick calc shows 72yrs, 270 days, 19hrs, 13min, and roughly 3 seconds to full. Of course assuming that the average of 11ft was an average done per square ft, and not just depth.
santa,
Great news. I am happy to report that your pond may take 18 fewer days to fill up than previously estimated, after taking those leap years into account.
The bad news is that the pond won't fill up any quicker. It's just that the calendar date of completion would be 18 days sooner than might be predicted.
PigHunter and bruisedsausage you both did your math well and 99, you hit it close enough too. The pump/volume/time program I used was based on rounding off to only four decimals during calculations and the input specs were based on a container which was one square mile by eleven feet deep and a pump that would pump one gallon per second. The program was supposed to account for leap years starting this year. The answer that the program came up with was 72 years, 252 days, three hours, 25 minutes, and 10 seconds. With the rounding off of some numbers to only four decimals, it could make a pretty good size error over that many seconds and gallons, so my numbers are merely approximate anyway.
This question came up to me a little differently by my grandson who asked how long would it take to drain a tank that was one mile wide by one mile long by one mile deep with a drain rate of one gallon per second. He had this on a quiz with multiple choice answers. In his problem, it would take over 30,000 years to drain.
hmmm Yeah I didn't account for leap years. Just did a 365 day year across the board.
santa Iam still weighting for my Remington M/31-F...
you pass me up Xmas..my Birthday is coming up in June?
Thank you santa!
hypothetically, i would save the time and effort and get yourself a reliable bass boat and hit the big lakes/rivers around your house. that would be way easier IMHO
Post an Answer
One acre = 43,560 square feet so we're talking 306,662,400 cubic feet for 160 acres 11 feet deep.
One US gallon is 0.133681 cubic feet so we're looking at 2,293,986,430 gallons for full pool. (at roughly room temp and sea level)
One US gallon weighes 8.345404 pounds (at roughly room temp and sea level). So, we're talking about 3600 gallons per hour.
Therefore, it will take 637,218 hours or about 72 years, 8 months, 9 days.
Of course my calculations and assumptions could be wrong...
Assuming that this is not a trick question, my best guess would be about 70 years, but I am no great mathematician.
santa,
Great news. I am happy to report that your pond may take 18 fewer days to fill up than previously estimated, after taking those leap years into account.
I think pig hunter got it. My quick calc shows 72yrs, 270 days, 19hrs, 13min, and roughly 3 seconds to full. Of course assuming that the average of 11ft was an average done per square ft, and not just depth.
The bad news is that the pond won't fill up any quicker. It's just that the calendar date of completion would be 18 days sooner than might be predicted.
santa Iam still weighting for my Remington M/31-F...
you pass me up Xmas..my Birthday is coming up in June?
Thank you santa!
PigHunter and bruisedsausage you both did your math well and 99, you hit it close enough too. The pump/volume/time program I used was based on rounding off to only four decimals during calculations and the input specs were based on a container which was one square mile by eleven feet deep and a pump that would pump one gallon per second. The program was supposed to account for leap years starting this year. The answer that the program came up with was 72 years, 252 days, three hours, 25 minutes, and 10 seconds. With the rounding off of some numbers to only four decimals, it could make a pretty good size error over that many seconds and gallons, so my numbers are merely approximate anyway.
This question came up to me a little differently by my grandson who asked how long would it take to drain a tank that was one mile wide by one mile long by one mile deep with a drain rate of one gallon per second. He had this on a quiz with multiple choice answers. In his problem, it would take over 30,000 years to drain.
hmmm Yeah I didn't account for leap years. Just did a 365 day year across the board.
hypothetically, i would save the time and effort and get yourself a reliable bass boat and hit the big lakes/rivers around your house. that would be way easier IMHO
Post an Answer